Inverse Function Of 1 X 2

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Mar 16, 2025 · 6 min read

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Unveiling the Inverse Function of f(x) = 1/x²: A Comprehensive Guide
The function f(x) = 1/x² presents a fascinating exploration into the world of inverse functions. Understanding its inverse requires a careful consideration of its domain and range, as well as the intricacies of function inversion itself. This article will delve deep into this topic, providing a comprehensive guide suitable for students and anyone interested in a deeper understanding of mathematical functions.
Understanding the Original Function: f(x) = 1/x²
Before we tackle the inverse, let's solidify our understanding of the original function, f(x) = 1/x².
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Domain: The domain of a function represents all possible input values (x) for which the function is defined. For f(x) = 1/x², the function is undefined when the denominator is zero, meaning x cannot be 0. Therefore, the domain is (-∞, 0) U (0, ∞). We use the union symbol (U) because the domain consists of two separate intervals.
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Range: The range represents all possible output values (y) that the function can produce. Since x² is always non-negative (0 or positive), 1/x² will always be positive. Furthermore, as x approaches 0, 1/x² approaches infinity, and as x approaches infinity, 1/x² approaches 0. Therefore, the range is (0, ∞). Note that the function never actually reaches 0.
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Graph: The graph of f(x) = 1/x² is a hyperbola. It exists in the first and second quadrants, asymptotic to both the x-axis and the y-axis. This visual representation clearly shows the domain and range limitations.
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Properties: The function is an even function, meaning f(-x) = f(x). This symmetry around the y-axis is evident in its graph. It's also strictly decreasing on the interval (0, ∞) and strictly increasing on the interval (-∞, 0).
Finding the Inverse Function
The process of finding the inverse of a function involves switching the roles of x and y and then solving for y. Let's apply this to f(x) = 1/x².
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Replace f(x) with y: This gives us y = 1/x².
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Swap x and y: This yields x = 1/y².
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Solve for y: To isolate y, we can perform the following steps:
- Multiply both sides by y²: xy² = 1
- Divide both sides by x: y² = 1/x
- Take the square root of both sides: y = ±√(1/x) This is crucial; remember the ± sign!
Therefore, we find that the inverse function is not a single function, but rather two functions:
- y = √(1/x) = 1/√x (This represents the positive square root)
- y = -√(1/x) = -1/√x (This represents the negative square root)
Domain and Range of the Inverse Functions
It's vital to analyze the domain and range of these inverse functions:
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For y = 1/√x:
- Domain: Since we have a square root in the denominator, x must be greater than 0 to avoid division by zero and to keep the argument of the square root non-negative. Therefore, the domain is (0, ∞).
- Range: The output (y) will always be positive since √x is always positive for x > 0 and 1 divided by a positive number remains positive. Therefore, the range is (0, ∞).
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For y = -1/√x:
- Domain: Similar to the above, the domain is (0, ∞) to avoid division by zero and maintain a valid square root.
- Range: The output (y) will always be negative because of the negative sign in front of 1/√x. Therefore, the range is (-∞, 0).
Understanding the Relationship between the Function and its Inverse
The original function, f(x) = 1/x², maps the domain (-∞, 0) U (0, ∞) to the range (0, ∞). However, due to the squaring operation, multiple values of x can map to the same positive value of y. For example, both x = 2 and x = -2 will result in y = 1/4. This is why the inverse is not a single function but rather two distinct functions. Each inverse function covers one branch of the original function's reflection across the line y = x.
The inverse functions, y = 1/√x and y = -1/√x, represent these reflected branches. If we were to restrict the domain of the original function to (0, ∞), then only the inverse function y = 1/√x would be valid. Similarly, if the original function's domain was restricted to (-∞, 0), then only y = -1/√x would be valid. This concept of restricting the domain to create a one-to-one function is crucial in many applications involving inverse functions.
Practical Applications and Implications
Understanding inverse functions is not merely a theoretical exercise. They have significant practical applications in various fields:
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Physics: Inverse functions are crucial in solving physics problems involving inverse square laws, such as Newton's Law of Universal Gravitation and Coulomb's Law. In these scenarios, one often needs to find the distance given the force, requiring the calculation of an inverse function.
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Engineering: Many engineering designs and calculations involve inverse functions. For instance, in electrical circuits, the relationship between voltage, current, and resistance is often expressed using Ohm's Law, and finding one quantity given the other may need an inverse relationship.
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Economics: Economic models frequently use inverse functions to represent relationships between variables, such as supply and demand. The inverse function allows you to determine the quantity demanded given a specific price, or vice versa.
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Computer Science: Inverse functions play a role in cryptography and data compression algorithms, where reversing an encryption or compression process often involves the calculation of an inverse function.
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Mathematics: Beyond these applications, inverse functions have fundamental importance within mathematics itself, serving as a core concept in calculus, especially in finding derivatives and integrals.
Graphical Representation of the Inverse Functions
To visualize the inverse relationship, consider graphing f(x) = 1/x² and its two inverse functions, y = 1/√x and y = -1/√x, on the same coordinate plane. You'll notice that the graphs of the inverse functions are reflections of the parts of the original function's graph about the line y = x. This reflection highlights the inherent relationship between a function and its inverse.
Conclusion
The inverse function of f(x) = 1/x² is not a single function but rather two distinct functions: y = 1/√x and y = -1/√x. This arises from the fact that the original function is not one-to-one across its entire domain. Understanding the domain and range of both the original function and its inverse functions is crucial for correctly interpreting and utilizing the inverse relationship. The concept of inverse functions, as we've explored through this detailed analysis, carries significant weight in various fields, illustrating its importance beyond theoretical mathematical concepts. Remember to always consider the context and the necessary restrictions on the domain to ensure the accurate application of inverse functions in solving problems. The complexity of this particular inverse emphasizes the need for careful analysis and a clear understanding of function properties.
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