Which Of The Following Is Not An Improper Integral

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May 11, 2025 · 5 min read

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Which of the Following is Not an Improper Integral? A Comprehensive Guide
Improper integrals represent a fascinating and sometimes tricky area of calculus. They extend the concept of definite integration to cases where either the interval of integration is unbounded or the integrand has an infinite discontinuity within the integration interval. Understanding the nuances of improper integrals is crucial for anyone working with advanced calculus, particularly in areas like probability, statistics, and physics. This article will delve into the definition of improper integrals, explore different types, and ultimately address the question: which of the following is not an improper integral? We will analyze various examples to solidify understanding.
Defining Improper Integrals: A Closer Look
A definite integral, as traditionally defined, involves integrating a function over a finite interval where the function is continuous. Improper integrals arise when one or both of these conditions are violated. There are two primary types:
Type 1: Infinite Limits of Integration
This type occurs when at least one limit of integration is infinite. The integral is expressed as:
- ∫<sub>a</sub><sup>∞</sup> f(x) dx or ∫<sub>-∞</sub><sup>b</sup> f(x) dx or ∫<sub>-∞</sub><sup>∞</sup> f(x) dx
The integral is evaluated as a limit:
- ∫<sub>a</sub><sup>∞</sup> f(x) dx = lim<sub>t→∞</sub> ∫<sub>a</sub><sup>t</sup> f(x) dx
If this limit exists and is finite, the improper integral converges; otherwise, it diverges. The same principle applies to integrals with a lower limit of -∞. Integrals with both limits infinite require splitting them into two separate integrals:
- ∫<sub>-∞</sub><sup>∞</sup> f(x) dx = lim<sub>t→-∞</sub> ∫<sub>t</sub><sup>0</sup> f(x) dx + lim<sub>t→∞</sub> ∫<sub>0</sub><sup>t</sup> f(x) dx
Type 2: Discontinuous Integrand
This type arises when the integrand, f(x), has a vertical asymptote (an infinite discontinuity) within the interval of integration [a, b]. This could occur at either endpoint or at an interior point. Let's consider the case where the discontinuity is at 'a':
- ∫<sub>a</sub><sup>b</sup> f(x) dx = lim<sub>t→a<sup>+</sup></sub> ∫<sub>t</sub><sup>b</sup> f(x) dx
Similarly, if the discontinuity is at 'b':
- ∫<sub>a</sub><sup>b</sup> f(x) dx = lim<sub>t→b<sup>-</sup></sub> ∫<sub>a</sub><sup>t</sup> f(x) dx
If the discontinuity occurs at an interior point 'c' within the interval (a, b), the integral must be split:
- ∫<sub>a</sub><sup>b</sup> f(x) dx = lim<sub>t→c<sup>-</sup></sub> ∫<sub>a</sub><sup>t</sup> f(x) dx + lim<sub>t→c<sup>+</sup></sub> ∫<sub>t</sub><sup>b</sup> f(x) dx
In each case, if the limit exists and is finite, the improper integral converges; otherwise, it diverges.
Identifying Non-Improper Integrals: Key Characteristics
Now, let's address the core question: how to identify an integral that is not improper. An integral is not improper if it satisfies both of the following conditions:
-
Finite Limits of Integration: The limits of integration, 'a' and 'b', must be finite real numbers.
-
Continuous Integrand: The integrand, f(x), must be continuous on the entire closed interval [a, b]. This means there are no vertical asymptotes or other discontinuities within the interval.
Any violation of either of these conditions results in an improper integral.
Examples: Distinguishing Improper and Non-Improper Integrals
Let's examine several examples to solidify our understanding.
Example 1: ∫<sub>1</sub><sup>2</sup> (x² + 3) dx
This is not an improper integral. The limits of integration are finite (1 and 2), and the integrand (x² + 3) is a polynomial, which is continuous everywhere.
Example 2: ∫<sub>0</sub><sup>∞</sup> e<sup>-x</sup> dx
This is an improper integral (Type 1) because the upper limit of integration is infinite.
Example 3: ∫<sub>-1</sub><sup>1</sup> 1/x dx
This is an improper integral (Type 2) because the integrand, 1/x, has an infinite discontinuity at x = 0, which lies within the interval [-1, 1].
Example 4: ∫<sub>1</sub><sup>∞</sup> 1/x² dx
This is an improper integral (Type 1 and potentially Type 2 depending on how you approach it). The upper limit is infinite, making it Type 1. While the integrand is continuous on [1, ∞), the infinite upper limit still qualifies it as improper.
Example 5: ∫<sub>0</sub><sup>1</sup> 1/√x dx
This is an improper integral (Type 2). The integrand, 1/√x, has an infinite discontinuity at x = 0, which is the lower limit of integration.
Example 6: ∫<sub>-∞</sub><sup>∞</sup> x e<sup>-x²</sup> dx
This is an improper integral (Type 1). The limits of integration are infinite.
Example 7: ∫<sub>0</sub><sup>π</sup> sin(x) dx
This is not an improper integral. The limits are finite, and sin(x) is continuous on [0, π].
Example 8: ∫<sub>0</sub><sup>1</sup> ln(x) dx
This is an improper integral (Type 2). The natural logarithm function, ln(x), has a vertical asymptote at x = 0.
Advanced Considerations and Techniques
While the basic principles are straightforward, evaluating improper integrals often requires advanced techniques. Some key methods include:
- Substitution: A powerful technique for simplifying integrals, often essential for improper integrals.
- Integration by Parts: Particularly useful when dealing with products of functions.
- Partial Fraction Decomposition: Helps to break down complex rational functions into simpler forms that are easier to integrate.
- Comparison Tests: Used to determine the convergence or divergence of improper integrals without explicitly calculating their value. These are especially helpful for integrals that are difficult or impossible to evaluate directly.
Conclusion: Mastering Improper Integrals
Improper integrals are an essential part of advanced calculus. Understanding their definition, types, and methods of evaluation is crucial for various applications. The key to determining whether an integral is improper lies in carefully examining the limits of integration and the continuity of the integrand across the integration interval. Remember, an integral is not improper if it has finite limits and a continuous integrand throughout the interval. By mastering these concepts and employing appropriate techniques, you can confidently navigate the complexities of improper integrals and apply them effectively in your mathematical pursuits.
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