Find Unit Vector Orthogonal To Two Vectors

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Apr 01, 2025 · 5 min read

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Finding a Unit Vector Orthogonal to Two Vectors: A Comprehensive Guide
Finding a unit vector orthogonal (perpendicular) to two given vectors is a fundamental concept in linear algebra with applications spanning various fields like physics, computer graphics, and machine learning. This comprehensive guide will walk you through the process, explaining the underlying mathematical principles and providing practical examples. We'll explore different methods and delve into the nuances of handling special cases.
Understanding Orthogonality and Unit Vectors
Before we dive into the methods, let's refresh our understanding of key terms:
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Orthogonal Vectors: Two vectors are orthogonal if their dot product is zero. Geometrically, this means they are perpendicular to each other.
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Unit Vector: A unit vector is a vector with a magnitude (or length) of 1. It's often used to represent direction without considering the magnitude.
Our goal is to find a vector that satisfies both conditions: it must be perpendicular to two given vectors, and its length must be 1.
Method 1: Using the Cross Product (for 3D Vectors)
The most straightforward method for finding a vector orthogonal to two other vectors is the cross product. This method is specifically applicable to three-dimensional vectors. The cross product of two vectors results in a vector that is orthogonal to both.
Let's say we have two 3D vectors:
- a = (a₁, a₂, a₃)
- b = (b₁, b₂, b₃)
The cross product c = a x b is calculated as follows:
c = (a₂b₃ - a₃b₂, a₃b₁ - a₁b₃, a₁b₂ - a₂b₁)
Important Note: The cross product is only defined for three-dimensional vectors. Attempting to use it with vectors of different dimensions will result in an error.
Example:
Let's find a vector orthogonal to a = (1, 2, 3) and b = (4, 5, 6).
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Calculate the cross product:
c = (26 - 35, 34 - 16, 15 - 24) = (-3, 6, -3)
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Verify orthogonality: Check that the dot product of c with both a and b is zero.
a • c = (1)(-3) + (2)(6) + (3)(-3) = -3 + 12 - 9 = 0 b • c = (4)(-3) + (5)(6) + (6)(-3) = -12 + 30 - 18 = 0
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Normalize to obtain the unit vector: To get a unit vector, we divide c by its magnitude:
||c|| = √((-3)² + 6² + (-3)²) = √(9 + 36 + 9) = √54 = 3√6
û = c / ||c|| = (-3/(3√6), 6/(3√6), -3/(3√6)) = (-1/√6, 2/√6, -1/√6)
Therefore, û = (-1/√6, 2/√6, -1/√6) is a unit vector orthogonal to both a and b.
Method 2: Using the Gram-Schmidt Process (for n-dimensional vectors)
The Gram-Schmidt process is a more general method that works for vectors of any dimension (2D, 3D, 4D, and so on). It's particularly useful when dealing with higher-dimensional vectors where the cross product isn't defined.
The Gram-Schmidt process orthogonalizes a set of vectors. To find a vector orthogonal to two given vectors, we can use a modified version of the process.
Let's say we have two vectors a and b.
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Normalize vector a:
ûₐ = a / ||a||
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Project vector b onto ûₐ:
proj<sub>ûₐ</sub>(b) = (b • ûₐ) ûₐ
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Find the orthogonal component:
v = b - proj<sub>ûₐ</sub>(b) This vector v is orthogonal to a.
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Normalize vector v:
ûᵥ = v / ||v|| This is the unit vector orthogonal to both a and b.
Example:
Let's use the same vectors as before: a = (1, 2, 3) and b = (4, 5, 6).
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Normalize a:
||a|| = √(1² + 2² + 3²) = √14 ûₐ = (1/√14, 2/√14, 3/√14)
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Project b onto ûₐ:
b • ûₐ = (4)(1/√14) + (5)(2/√14) + (6)(3/√14) = 32/√14 proj<sub>ûₐ</sub>(b) = (32/√14) * (1/√14, 2/√14, 3/√14) = (32/14, 64/14, 96/14) = (16/7, 32/7, 48/7)
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Find the orthogonal component:
v = (4, 5, 6) - (16/7, 32/7, 48/7) = (12/7, -3/7, -6/7)
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Normalize v:
||v|| = √((12/7)² + (-3/7)² + (-6/7)²) = 3√6/7 ûᵥ = (12/(3√42), -3/(3√42), -6/(3√42)) = (4/√42, -1/√42, -2/√42)
Therefore, ûᵥ = (4/√42, -1/√42, -2/√42) is another unit vector orthogonal to both a and b. Note that this is different from the vector we obtained using the cross product – this is because there are two possible unit vectors orthogonal to any two vectors in 3D space.
Handling Special Cases
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Collinear Vectors: If the two given vectors are collinear (parallel), then there are infinitely many vectors orthogonal to them. The cross product will yield the zero vector. The Gram-Schmidt process will show that the orthogonal component is also the zero vector. In this scenario, choosing an orthogonal vector requires additional constraints or information.
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Zero Vectors: If one or both of the input vectors are zero vectors, the concept of orthogonality becomes trivial. The cross product and the Gram-Schmidt process will not yield a meaningful result. You'll need to define your problem differently, perhaps by specifying additional constraints.
Applications
Finding unit vectors orthogonal to two vectors has widespread applications:
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Computer Graphics: Used in calculating surface normals for lighting and shading calculations.
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Physics: Determining the direction of forces or torques.
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Machine Learning: Used in dimensionality reduction techniques and feature engineering.
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Robotics: Essential for calculating joint angles and robot movements.
Conclusion
Finding a unit vector orthogonal to two given vectors is a crucial task with numerous practical applications. This guide presented two primary methods: the cross product (for 3D vectors) and the Gram-Schmidt process (for any dimension). Understanding these methods, along with awareness of special cases, equips you with the necessary tools to tackle these problems effectively. Remember that in 3D space, there are always two unit vectors orthogonal to any two given linearly independent vectors. Choosing one over the other depends on the specific context of your application. Choosing the right method will depend heavily on the dimension of the vectors you are working with. The cross product offers a quicker calculation for 3D vectors, whereas the Gram-Schmidt process offers more generality across any dimension.
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